Reputation: 345
I have an image file named "Image.png", and it is saved in my main bundle (right beside the ViewController.swift file in the Project Navigator hierarchy). I want to save a copy of this image to the temporary directory. I've never done it before, what code could I use please?
Upvotes: 8
Views: 20495
Reputation: 2774
Here's the answer in Swift 5
/**
* Copy a resource from the bundle to the temp directory.
* Returns either URL of location in temp directory, or nil upon failure.
*
* Example: copyBundleResourceToTemporaryDirectory("kittens", "jpg")
*/
public func copyBundleResourceToTemporaryDirectory(resourceName: String, fileExtension: String) -> URL?
{
// Get the file path in the bundle
if let bundleURL = Bundle.main.url(forResource: resourceName, withExtension: fileExtension) {
let tempDirectoryURL = URL(fileURLWithPath: NSTemporaryDirectory(), isDirectory: true)
// Create a destination URL.
let targetURL = tempDirectoryURL.appendingPathComponent(resourceName).appendingPathExtension(fileExtension)
// Copy the file.
do {
try FileManager.default.copyItem(at: bundleURL, to: targetURL)
return targetURL
} catch let error {
print("Unable to copy file: \(error)")
}
}
return nil
}
I'd recommend to read this article to learn more about temporary files
Upvotes: 5
Reputation: 1187
Swift 4.x version of mszaro's answer
/**
* Copy a resource from the bundle to the temp directory.
* Returns either NSURL of location in temp directory, or nil upon failure.
*
* Example: copyBundleResourceToTemporaryDirectory("kittens", "jpg")
*/
public func copyBundleResourceToTemporaryDirectory(resourceName: String, fileExtension: String) -> NSURL?
{
// Get the file path in the bundle
if let bundleURL = Bundle.main.url(forResource: resourceName, withExtension: fileExtension) {
let tempDirectoryURL = NSURL.fileURL(withPath: NSTemporaryDirectory(), isDirectory: true)
// Create a destination URL.
let targetURL = tempDirectoryURL.appendingPathComponent("\(resourceName).\(fileExtension)")
// Copy the file.
do {
try FileManager.default.copyItem(at: bundleURL, to: targetURL)
return targetURL as NSURL
} catch let error {
NSLog("Unable to copy file: \(error)")
}
}
return nil
}
Upvotes: 9
Reputation: 1372
Something like this should do the trick. I'm assuming you wanted the answer in Swift.
/**
* Copy a resource from the bundle to the temp directory.
* Returns either NSURL of location in temp directory, or nil upon failure.
*
* Example: copyBundleResourceToTemporaryDirectory("kittens", "jpg")
*/
public func copyBundleResourceToTemporaryDirectory(resourceName: String, fileExtension: String) -> NSURL?
{
// Get the file path in the bundle
if let bundleURL = NSBundle.mainBundle().URLForResource(resourceName, withExtension: fileExtension) {
let tempDirectoryURL = NSURL.fileURLWithPath(NSTemporaryDirectory(), isDirectory: true)
// Create a destination URL.
let targetURL = tempDirectoryURL.URLByAppendingPathComponent("\(resourceName).\(fileExtension)")
// Copy the file.
do {
try NSFileManager.defaultManager().copyItemAtURL(bundleURL, toURL: targetURL)
return targetURL
} catch let error {
NSLog("Unable to copy file: \(error)")
}
}
return nil
}
Although, I'm not really sure why you would want to do this rather than directly accessing the bundle resource.
Upvotes: 26