Reputation: 301
I'm listing out some dates in my PHP application which results in something like the following:
April2016May2016June2016
etc.
I'm trying to use preg_split
to format them like this:
array('April 2016', 'May 2016', 'June 2016')
I used an online Regular Expression editor to determine how to detect for 4 consecutive numbers and here's how far I've gotten:
Note: I am also removing all white space - ideally this would be better if it only removed white space if there were more than 2 spaces i.e. hello world
would not be altered but hello world
would.
preg_split('/\d\d\d\d/g', preg_replace('!\s+!', '', $sidebar_contents));
Using the above, I get an error suggesting that the g identifier is not valid assuming because it's not preg_match_all
- removing the g result in the following:
Thanks for any help!
Upvotes: 3
Views: 166
Reputation: 626926
Here is a way to achieve what you want with 1 call to preg_match_all
and using an array_map
after:
preg_match_all('~(\p{L}+)(\d+)~', "April2016May2016June2016", $m);
$result = array_map(function($k, $v) { return $k . " " . $v; }, $m[1], $m[2]);
print_r($result);
See the regex demo and an IDEONE demo.
The pattern means:
(\p{L}+)
- match and capture into Group 1 (will be accessible after matching via $m[1]
) one or more letters(\d+)
- match and capture into Group 2 (will be accessible after matching via $m[2]
) one or more digits.With array_map
, we just join the values from Group 1 and 2 with a space.
Alternative: fill out the resulting array inside a preg_replace_callback
(just one pass!):
$result = array();
preg_replace_callback('~(\p{L}+)(\d+)~', function($m) use (&$result) {
array_push($result, $m[1] . " " . $m[2]);
}, "April2016May2016June2016");
print_r($result);
See the IDEONE demo.
Upvotes: 2
Reputation: 47099
You can insert the space and then split:
<?php
$input = "April2016May2016June2016";
var_dump(preg_split('/(?<=\d)(?!\d|$)/i',
preg_replace('/(?<!\d)(?=\d)/', ' ', $input)));
?>
Outputs:
array(3) {
[0]=>
string(10) "April 2016"
[1]=>
string(8) "May 2016"
[2]=>
string(9) "June 2016"
}
Upvotes: 2
Reputation: 2557
Try this:
$str = "April2016May2016June2016";
preg_match_all("/[a-z]+\\s\\d+/i", preg_replace("/([a-z]+)(\\d+)/i", "$1 $2", $str), $matches);
print_r($matches[0]);
Output:
Array
(
[0] => April 2016
[1] => May 2016
[2] => June 2016
)
Upvotes: 1