CODEWITHSUNDEEP
pythonregex
deptrai
deptrai

Reputation: 147

Filter contents with brackets into a Python list

I have tried to filter the content within the round brackets with regex. 

s = "(time.timestamp > '2019-12-04 10:16:57+0100' AND car.Audi > 5) AND (time.timestamp > '2019-12-04 10:16:57+0100' AND car.VW > 5) OR (time.timestamp > '2019-12-04 10:16:57+0100' AND car.BMW > 5)"

What I would like to have as a return is a list of these contents and the ANDs 

list = [
         "(time.timestamp > '2019-12-04 10:16:57+0100' AND car.Audi > 5)",
         "AND",
         "(time.timestamp > '2019-12-04 10:16:57+0100' AND car.VW > 5)",
         "OR",
         "(time.timestamp > '2019-12-04 10:16:57+0100' AND car.BMW > 5)"
        ]

I tried re.split(r'\)\s*(AND|OR)\s*\(', s) but some of the brackets were removed. 

[
"(events.timestamp > '2019-12-04 10:16:57+0100' AND event_type.engine_error > 5",
 'AND', 
"events.timestamp > '2019-12-04 10:16:57+0100' AND event_type.turtle_lamp > 5)",
 ...
]

have you an idea how I can solve it best?

it doesn't have to be solved with Regex either.

Upvotes: 3

Views: 462

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627103

The parentheses are removed because they are part of the consuming pattern. All consumed chars that are not captured are removed with re.split.

Wrap the parentheses with lookarounds, a lookbehind at the start and a lookahead at the end:

re.split(r'(?<=\))\s*(AND|OR)\s*(?=\()', s)
           ^^^^^^^              ^^^^^^

Now, (?<=\)) matches a location that is immediately preceded with ) and (?=\() matches a location immediately followed with (.

Upvotes: 2

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