CODEWITHSUNDEEP
verilogsystem-veriloguvm
newbie
newbie

Reputation: 4789

Systemverilog dynamic casting issues

I've a code snippet like following in my testbench

function void write_to_port( my_data_type_base data );
    my_data_type_extended data_ext;
    if(!$cast(data_ext, data));
        `uvm_error(get_type_name(), "failed to cast");
   `uvm_info(get_name(), $psprintf("data_ext :\n%s", data_ext.sprint()), UVM_MEDIUM)
  // write data_ext out to another port....
endfunction

When I run it, I'm getting uvm_error as "failed to cast." I'm not quire sure why $cast is not returning 1. As you can see, I'm printing out the extended class data item after casting with uvm_info. I can see that it's being cast properly. If I don't use $cast with if condition, I don't get any runtime error. Isn't it a good coding practice to always use if with dynamic cast to check if $cast is returning 1 ?

What might be the reason behind cast not returning 1 in above case?

Upvotes: 1

Views: 1473

Answers (1)

Tim
Tim

Reputation: 35923

I think the semicolon on the line with 'if' does not belong?

I think that consumes the if statement, and then the uvm_error executes regardless of how if evaluates:

if(!$cast(data_ext, data)); <- no semicolon
    `uvm_error(get_type_name(), "failed to cast");

Upvotes: 2

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