CODEWITHSUNDEEP
veriloghardwarehdlregister-transfer-level
Veridian
Veridian

Reputation: 3657

Shift a number left in verilog and only retain upper bits

I have the following wires in verilog:

wire [15:0] mywire;
wire [7:0] mywire_shifted
wire [4:0] shiftamount;

I want to shift mywire left by some amount, but only retain the upper 8 bits:

assign mywire_shifted = (mywire << shiftamount) >> 8;

Is there a cleaner way to do this?

Perhaps something like this:

assign {mywire_shifted,8'0} = mywire << shiftamount;

Upvotes: 0

Views: 1493

Answers (1)

dave_59
dave_59

Reputation: 42613

I think your first solution is clean. But you could also do

assign mywire_shifted = mywire[shiftamount+8 +: 8];

This says starting from the LSB (shiftamount+8) return the next MSB(higher) 8 bits.

Upvotes: 5

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