Reputation: 3
I need your help. I have a VHDL with nested condition and I would like to redraw it into a schematic. I think I should use one 2bit mux and 4bit mux. Is there anyone who can help me please? I tried google it but I didn't find anything that can help me.
process (a,b,c,d) begin
y <= '0';
z <= b;
if d='1' then
y <= b;
if a = '0' then
y <= c;
end if;
z <= '1';
else
y <= '1';
z <= d;
end if;
end process;
a,b,c,d are std_logic in
z, y are std_logic out
Upvotes: 0
Views: 516
Reputation: 335
This a code for a 4-bit mux you can easily modify to make 2 bit
LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
ENTITY mux_4_1 IS
PORT (
a : IN STD_LOGIC_VECTOR(3 DOWNTO 0);
s : IN STD_LOGIC_VECTOR(1 DOWNTO 0);
b : OUT STD_LOGIC);
END ENTITY;
ARCHITECTURE behavioural OF mux_4_1 IS
BEGIN
PROCESS (a, s)
BEGIN
IF s = "00" THEN
b <= a(0);
ELSIF s = "01" THEN
b <= a(1);
ELSIF s = "10" THEN
b <= a(2);
ELSE
b <= a(3);
END IF;
END PROCESS;
END ARCHITECTURE;
Upvotes: 1